CaCO3→CO2+CaOCaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3CaCO3) in the chemical reaction shown. What is the total mass of the products?
• 30 grams
• 60 grams
• 10 grams
• 15 grams
60 grams
To determine the total mass of the products, we need to calculate the molar masses of CO2 and CaO, and then add them together.
1. Calculate the molar mass of CO2 (carbon dioxide):
- One carbon atom has a molar mass of 12.01 g/mol.
- Two oxygen atoms have a combined molar mass of 2 * 16.00 g/mol = 32.00 g/mol.
- So, the molar mass of CO2 is 12.01 g/mol + 32.00 g/mol = 44.01 g/mol.
2. Calculate the molar mass of CaO (calcium oxide):
- One calcium atom has a molar mass of 40.08 g/mol.
- One oxygen atom has a molar mass of 16.00 g/mol.
- So, the molar mass of CaO is 40.08 g/mol + 16.00 g/mol = 56.08 g/mol.
3. The balanced chemical equation shows that 1 mole of CaCO3 produces 1 mole of CO2 and 1 mole of CaO.
- The molar mass of CaCO3 is 40.08 g/mol (for Ca) + 12.01 g/mol (for C) + (3 * 16.00 g/mol) (for three O) = 100.09 g/mol.
4. Now, we can calculate the mass of the products:
- For every 1 mole of CaCO3, we get 1 mole of CO2 (44.01 g/mol) and 1 mole of CaO (56.08 g/mol).
- Since the molar mass of CaCO3 is 100.09 g/mol, we can calculate the mass of the products as follows:
- Mass of CO2 = (1 mole of CO2 / 1 mole of CaCO3) * (44.01 g/mol) * (30 g / 100.09 g/mol)
- Mass of CaO = (1 mole of CaO / 1 mole of CaCO3) * (56.08 g/mol) * (30 g / 100.09 g/mol)
- Total mass of the products = Mass of CO2 + Mass of CaO.
5. Using the given values and the calculations above, we can determine the total mass of the products.
Total mass of the products ≈ (0.4401 * 30) g + (0.5608 * 30) g
≈ 13.203 g + 16.824 g
≈ 30.027 g.
Therefore, the total mass of the products is approximately 30 grams.
So, the correct answer is:
• 30 grams.
To determine the total mass of the products, we need to find the molar mass of each product (CO2 and CaO), and then calculate the total mass by adding them together.
The molar mass of CO2 is 12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen = 44.01 g/mol.
The molar mass of CaO is 40.08 g/mol for calcium + 16.00 g/mol for oxygen = 56.08 g/mol.
Now, let's calculate the total mass of the products:
(1 mole of CaCO3) → (1 mole of CO2) + (1 mole of CaO)
Since the balanced chemical equation shows a 1:1:1 ratio between CaCO3, CO2, and CaO, we know that the molar mass of CaCO3 is equal to the molar mass of CO2 and CaO.
Therefore, the total mass of the products is equal to the mass of calcium carbonate, which is 30 grams.
So, the correct answer is:
• 30 grams