Login or Sign Up

Ask a New Question

A bag contains 6 red balls and 5 black balls,2 balls are picked,one after the other,find the probability that

(a) both are black
(b) the first is black
(c) both are the same colour
Given that
(1) it is without replacement
(2) it is with replacement

(a) Without replacement: 5/11 * 4/10 = 20/110 = 2/11

(b) Without replacement: 5/11
(c) Without replacement: 10/11

Did you know?

Did you know that when picking balls from a bag without replacement, the probability of selecting two black balls from a bag containing 6 red balls and 5 black balls is 5/55? This means that out of all the possible combinations, there are 5 successful outcomes. Furthermore, if you are interested in the probability of picking a black ball on the first try, regardless of the second pick, it is 5/11. This is because there are 11 total balls in the bag, with 5 of them being black. Lastly, if you want to determine the probability of picking two balls of the same color, it differs depending on whether replacement is allowed or not. If replacement is not allowed, the probability of picking two balls of the same color is 26/55, as there are 26 possible color combinations. However, if replacement is allowed, then the probability is 30/121, which means there are 30 possible color combinations out of 121. Understanding probabilities in different scenarios can help in decision-making and predicting outcomes!