A bag contains 10 balls of which 6 are red and the rest are white and blue and of equal numbers,if a ball is picked at random, find the probability that it is

(a) either white or red
(b) not red
(c) blue or red
(d) white

(a) P(white or red) = P(white) + P(red) = 6/10 + 6/10 = 12/10 = 6/5

(b) P(not red) = P(white) + P(blue) = 4/10 + 4/10 = 8/10

(c) P(blue or red) = P(blue) + P(red) = 4/10 + 6/10 = 10/10 = 1

(d) P(white) = 6/10