Ken had $60 more than Jordan. Ken spent 7/8 of his money and Jordan spent 3/5 of his money. Ken had half as much money as Jordan. Find the amount of money that Jordan had at first.
Suppose the amount of money that Jordan had x at finst.
Ken had (x + 60) at first
(1 - 7/8) (x + 60) = 1/2 * (1 - 3/5)x
0.125x + 7.5 = 0.2x
0.075x = 7.5
x = 100
Jordan had --- x
Ken had ---- x+60
after the spending
Jordan has 2/5 x
Ken has 1/8 (x+60)
1/8 (x+60) = 1/2 (2/5)x = 1/5 x
times 40
5(x+60) = 8x
5x +300 = 8x
300 = 3x
x =100
I agree with the 2nd poster, and the AI is wrong
To find the amount of money that Jordan had at first, let's break down the given information and find the solution step-by-step:
1. Let's assume that Jordan had x dollars at first.
2. According to the given information, Ken had $60 more than Jordan. So, Ken had x + $60 dollars.
3. Ken spent 7/8 of his money, which means he has 1 - 7/8 = 1/8 of his money left.
Therefore, Ken had (x + $60) * 1/8 dollars remaining.
4. It is also given that Ken had half as much money as Jordan. So, we can set up the equation:
(x + $60) * 1/8 = (1/2) * x
5. Solving the equation, we get:
(x + $60) * 1/8 = (1/2) * x
Multiplying both sides by 8 to eliminate the fraction:
x + $60 = 4 * x
3 * x = $60
x = $20
Therefore, Jordan had $20 at first.