can someone help me with this πŸ˜­βœ‹

Tim and Jan started at the same spot. Tim went 3 miles east and 4 miles north. Jan went 12 miles west and 16 miles north. How far apart are​ they? Round your answer to the nearest tenth.

tysm to anyone that helps <3

that's incorrect...

AAAaannndd the bot gets it wrong yet again!

d = √((12-3)^2+(16-4)^2) = √(9^2+12^2) = 15

oops ...

d = √((12+3)^2+(16-4)^2) = √(15^2+12^2) = 19.2

THANK YOUU :D this gave me a 100%!

i will write this down in my notes <3

Tim and Jan started at their home. Tim went 6 miles east and 8 miles north. Jan went 15 miles west and 20 miles north. How far apart are​ they? Round your answer to the nearest tenth.

Of course! I can help you with that problem.

To find out how far apart Tim and Jan are, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, we can consider the distance Tim traveled as one side of a right triangle, and the distance Jan traveled as the other side. The distance between them will be the length of the hypotenuse.

First, let's calculate the side lengths Tim and Jan traveled:

Tim: 3 miles east and 4 miles north
Jan: 12 miles west and 16 miles north

To simplify the problem, we can assume that traveling east is positive and traveling west is negative. Similarly, traveling north is positive and traveling south is negative.

So, Tim traveled 3 miles east and 4 miles north, which means his position can be represented as (3, 4).

Jan traveled 12 miles west and 16 miles north, which can be represented as (-12, 16).

Now, let's calculate the distance between their positions:

Using the Pythagorean theorem, we have:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Substituting the values, we have:
Distance = sqrt(((-12) - 3)^2 + (16 - 4)^2)

Calculating this expression:
Distance = sqrt((-15)^2 + (12)^2)
Distance = sqrt(225 + 144)
Distance = sqrt(369)
Distance β‰ˆ 19.2

So, Tim and Jan are approximately 19.2 miles apart.

Remember to always double-check the calculations and units to ensure accuracy.

The distance between Tim and Jan is 20.2 miles.