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Use inverse operations to solve each equation. Explain each step and identify the property used to reach step.
19 = h3 āˆ’ 8

Solution:

Step 1: Add 8 to both sides of the equation.
19 + 8 = h3 āˆ’ 8 + 8
Property used: Addition Property of Equality

Step 2: Simplify the equation.
27 = h3
Property used: None

Step 3: Divide both sides of the equation by 3.
27/3 = h3/3
Property used: Division Property of Equality

Step 4: Simplify the equation.
9 = h
Property used: None

Therefore, the solution to the equation is h = 9.

jeez- tysm

Don't trust the robot tutor, it is wrong most of the time for math questions.

I assume you meant:
19 = h^3 āˆ’ 8
if you meant multiplication, the constant is usually written first
and it would have been 3h

so
h^3 = 27
h = 27^(1/3) = 3

(if you indeed meant 3h, then yes, the answer is h = 9)

To solve the equation 19 = h3 - 8 using inverse operations, we need to isolate the variable h.

Step 1: Start by undoing the subtraction. Since the term being subtracted is -8, we'll add 8 to both sides of the equation to eliminate the -8 on the right side:

19 + 8 = h3 - 8 + 8

Step 2: Simplify both sides of the equation:

27 = h3

Step 3: Now, we have h3 = 27. To isolate h, we need to undo the exponentiation. Since the exponent is 3, we can use the cube root on both sides:

āˆ›(h3) = āˆ›27

Step 4: Simplify both sides by taking the cube root of 27:

h = 3

The property used in step 1 is the additive property of equality, which allows us to add the same value to both sides of the equation. In step 4, we used the property of taking the cube root to undo the exponentiation.