Question

Given the quadratic relation y = -x^2 + 6x - 6,

a) write the equation in vertex form

Answer 1

y = -x^2 + 6x - 6

= -1(x^2 - 6x + .... ) - 6
= -1(x^2 - 6x + 9 - 9) - 6
= -1( (x-3)^2 - 9) - 6
= -(x-3)^2 + 9 - 6
= -(x - 3)^2 + 3