Moby then goes up the other side of the halfpipe and stops. If that trip also took five seconds, what was Moby's acceleration?
To find Moby's acceleration, we need to use the equation for acceleration:
Acceleration (a) = (Final velocity - Initial velocity) / Time
In this case, Moby's final velocity is 0 m/s because he stops, his initial velocity is also 0 m/s because he starts from rest, and the time is 5 seconds.
So, plugging in the values into the equation, we get:
Acceleration (a) = (0 m/s - 0 m/s) / 5 s
Since the velocity difference is 0, the numerator becomes 0.
Acceleration (a) = 0 m/s^2
Therefore, Moby's acceleration is 0 m/s^2.