CaCO3→CO2+CaOCaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3CaCO3) in the chemical reaction shown. What is the total mass of the products?
• 60 grams
• 10 grams
• 30 grams
• 15 grams
Well, well, well. Looks like we've got ourselves a chemical equation here. Let me put on my scientist hat and crunch some numbers for you.
The equation tells us that 1 mole of CaCO3 (molar mass of 100 g) yields 1 mole of CO2 (molar mass of 44 g) and 1 mole of CaO (molar mass of 56 g).
So, if we have 30 grams of CaCO3, we can calculate the moles: 30 g / 100 g/mol = 0.3 moles of CaCO3.
Since the equation states a 1:1:1 ratio, we know that we'll get 0.3 moles of both CO2 and CaO.
Now, to find the mass of the products, we multiply the moles by their respective molar masses:
0.3 moles of CO2 x 44 g/mol = 13.2 grams of CO2
0.3 moles of CaO x 56 g/mol = 16.8 grams of CaO
Adding these two products together, we get a total mass of 13.2 grams + 16.8 grams = 30 grams.
So, the correct answer is 30 grams! Voila!
To determine the total mass of the products, we need to calculate the molar mass of each product and then multiply it by the respective molar ratio in the balanced equation.
The balanced equation is: CaCO3 → CO2 + CaO
1. Calculate the molar mass of each product:
- CO2: The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. So the molar mass of CO2 is 12.01 + (2 * 16.00) = 44.01 g/mol.
- CaO: The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol. So the molar mass of CaO is 40.08 + 16.00 = 56.08 g/mol.
2. Calculate the molar ratio of the products:
- From the balanced equation, we can see that 1 mol of CaCO3 produces 1 mol of CO2 and 1 mol of CaO.
3. Convert the given mass of CaCO3 to moles:
- The molar mass of CaCO3 is 40.08 + 12.01 + (3 * 16.00) = 100.09 g/mol.
- To convert grams to moles, divide the given mass by the molar mass: 30 g / 100.09 g/mol = 0.2998 mol.
4. Determine the mass of each product:
- CO2: Multiply the moles of CaCO3 (0.2998 mol) by the molar ratio (1 mol CO2 / 1 mol CaCO3) and the molar mass of CO2 (44.01 g/mol): 0.2998 mol * (1 mol CO2 / 1 mol CaCO3) * 44.01 g/mol = 13.19 g.
- CaO: Multiply the moles of CaCO3 (0.2998 mol) by the molar ratio (1 mol CaO / 1 mol CaCO3) and the molar mass of CaO (56.08 g/mol): 0.2998 mol * (1 mol CaO / 1 mol CaCO3) * 56.08 g/mol = 16.82 g.
5. Calculate the total mass of the products:
- Total mass = mass of CO2 + mass of CaO = 13.19 g + 16.82 g = 29.01 g.
Therefore, the total mass of the products is approximately 29.01 grams.