1.Write the following in logarithmic form: a^(2c+1)=3b-d
2. Rewrite the expression as a single logarithm: 1/3In x+4[In(x+1)-1/2In(x-2)]
3. How does the graph of the transformed function x= − log3(5x −1)+2 compare to the graph of its parent function compare to the graph of its parent function f(x)= log3 x?
a^(2c+1)=3b-d
loga3b-d = 2c+1
or maybe you want
(2c+1) log a = log(3b-d) ... for any log base
1/3In x+4[In(x+1)-1/2In(x-2)]
ln∛x + ln(x+1)⁴ - ln√(x-2)
ln [ ∛x (x+1)⁴ / √(x-2) ]