the points a, b and c have position vectors a 2i + j - k, b = 3i + 4j - 2k and c = 5i - j + 2k respectively relative to a fixed origin o. the position e lies on ba produced so that be = 3ba. write down the position vector is. the line ce cuts the line ad at x. find the position vector of x
How about you go and do your own work for once instead of screwing around
a-b = -i-3j+k
so e = a + 2(a-b) = _____
no idea where d is, so same for x.