Construct triangle abc with ab=8cm bc=8cm ac=7cm
Bisect angle abc and let the bisector meet ac at d produce bdto p such that bd=do join ap and cp
To construct triangle ABC with AB = 8 cm, BC = 8 cm, and AC = 7 cm, follow these steps:
1. Start by drawing a straight line segment AB of length 8 cm.
2. Use a compass to draw a circle with a radius of 8 cm centered at point A. This circle will intersect AB at point C.
3. Draw a straight line segment BC connecting points B and C.
4. Next, draw a circle with a radius of 7 cm centered at point B. This circle will intersect BC at point D and AC at point E (not labeled in the question).
5. Use a compass to draw a circle with a radius larger than half the line segment BD, centered at point B. Label the point where the circle intersects the previously drawn bisector as P.
6. Draw a straight line segment BD connecting points B and D. Measure the length BD to ensure it is equal to DO.
7. Finally, draw two straight lines AP and CP, connecting points A and P, and points C and P, respectively.
Your construction should now be complete, and you have triangle ABC with AB = 8 cm, BC = 8 cm, and AC = 7 cm, as well as the bisector of angle ABC meeting AC at point D, and the line segment BD bisected and extended to point P such that BD = DO.