A lever with an effort arm of 10 meters and a load arm of 2 meters is used to lift an object weighing 220 Newtons to a height of 4 meters. If 400 Joules of work is done, how much force must have been applied?
Answers for Levers Quick Check.
1: A= 3:2:1
2: C= 3
3: B= Class 1 and 3
4: A= 600 J
5: A= 100 N
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Cool Cat is 100% correct! Thank you so much; this helped me check my answers! :)
Coolcat is 100% correct.
To determine the force that must have been applied, we can use the principles of work and lever systems.
First, let's calculate the work done using the formula:
Work = Force x Distance
In this case, the work done is given as 400 Joules, so we have:
400 Joules = Force x Distance
Since the distance is 4 meters, we can rewrite the equation as:
400 Joules = Force x 4 meters
Now, let's consider the lever system. A lever is a simple machine that consists of a rigid bar or beam that pivots around a fixed point called a fulcrum. It can be used to amplify or redirect forces.
In this scenario, the effort arm of the lever is 10 meters, and the load arm is 2 meters. The weight of the object being lifted is given as 220 Newtons.
To find the force required, we can use the concept of moments (or torque) in a lever system. The principle of moments states that the sum of the clockwise moments about the fulcrum is equal to the sum of the counterclockwise moments.
In this case, we can equate the moments as:
(Force x Load Arm) = (Weight x Effort Arm)
Solving for Force, we have:
Force = (Weight x Effort Arm) / Load Arm
Plugging in the given values:
Force = (220 Newtons x 10 meters) / 2 meters
Force = 2200 Newtons / 2 meters
Force = 1100 Newtons
Therefore, the force that must have been applied to lift the object is 1100 Newtons.