Suppose the vertices of ABC are A (4,3) B (-2,2) C (0,0). Describe the translation used to form the image triangle: A(0,3) B(-6,2) C(-4,0)
A: 4 units left and 4 units down
B: 4 units left
C: 4 units right and 4 units up
D: 4 units right
Hmm, it seems like the image triangle was just trying to escape to the left! So the correct option would be B: 4 units left. It's always good to keep an eye on those sneaky triangles!
To describe the translation used to form the image triangle A'(0,3) B'(-6,2) C'(-4,0) from the original triangle ABC, we can compare the coordinates of the corresponding vertices.
Let's start with vertex A. The x-coordinate of A has changed from 4 to 0, which means that A has been moved 4 units to the left. The y-coordinate of A remains the same at 3. So, the translation for vertex A is 4 units left.
Next, let's consider vertex B. The x-coordinate of B has changed from -2 to -6, indicating a movement of 4 units to the left. The y-coordinate of B remains the same at 2. Thus, the translation for vertex B is also 4 units left.
Lastly, let's analyze vertex C. The x-coordinate of C has changed from 0 to -4, indicating a movement of 4 units to the left. The y-coordinate of C has changed from 0 to 4, indicating a movement of 4 units up. Therefore, the translation for vertex C is 4 units left and 4 units up.
Thus, the correct answer is C: 4 units right and 4 units up.