What is the nth term of the progression 27,9,3,...
looks like you dividing by 3 from one term to the next
So you could just keep going or
a = 27
r = 1/3
term(n) = a r^(n-1)
= 27(1/3)^(n-1)
= 3^3 * 3^(1-n)
= 3^(4-n)
So you could just keep going or
a = 27
r = 1/3
term(n) = a r^(n-1)
= 27(1/3)^(n-1)
= 3^3 * 3^(1-n)
= 3^(4-n)