container a and container b have leaks. container a has 800 ml of water, and is leaking 6 ml per minute. container b has 1000 ml, and is leaking 10 ml per minute. how many minutes, m, will it take for two containers to have the same amount of water?
To find the number of minutes it will take for both containers to have the same amount of water, we can set up an equation.
Let's say 'm' represents the number of minutes.
For container A, the initial amount of water is 800 ml, and it is leaking 6 ml per minute. So at time 'm', the amount of water left in container A is given by: 800 - 6m.
Similarly, for container B, the initial amount of water is 1000 ml, and it is leaking 10 ml per minute. So at time 'm', the amount of water left in container B is given by: 1000 - 10m.
We want the amount of water in both containers to be the same at time 'm', so we can set up the equation:
800 - 6m = 1000 - 10m
Simplifying the equation, we get:
-6m + 10m = 1000 - 800
4m = 200
Dividing both sides by 4, we find:
m = 50
Therefore, it will take 50 minutes for both containers to have the same amount of water.