Question

Calculate the no of mole of cacl2 that can be optained from 30g of caco3 in the percent of hcl

Answer 1

CaCO3 + 2HCl ==> CaCl2 + CO2 + H2O

mols CaCO3 = grams/molar mass = 30/100 = 0.30
Then 1 mol CaCO3 Will produce 1 mol CaCl2 = 0.30 g
grams CaCl2 = mols CaCl2 x molar mass CaCl2 = ?