Calculate the mass of CaCl2 formed when 5 mole of chlorine reacts with calcium metal
The mass of CaCl2 formed when 5 mole of chlorine reacts with calcium metal is 140 g.
This can be calculated using the following equation:
Mass of CaCl2 = (5 mol Cl x 70.9 g/mol Cl) + (5 mol Ca x 40.1 g/mol Ca) = 140 g
calculete the mass of CaCL2 formed when 5 moles of chlorine reacts with calcium metal. solution
use;- ca + cl2 =cacl2 (at. weight ca =40gm,cl=35.5gm)
To calculate the mass of CaCl2 formed when 5 moles of chlorine react with calcium metal, we need to use the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction of chlorine (Cl2) with calcium metal (Ca) is:
2 Ca + Cl2 -> 2 CaCl2
From the balanced equation, we can see that 2 moles of calcium react with 1 mole of chlorine to form 2 moles of calcium chloride (CaCl2).
Given that we have 5 moles of chlorine (Cl2), we can use stoichiometry to determine the moles of calcium chloride formed.
5 moles of Cl2 x (2 moles CaCl2 / 1 mole Cl2) = 10 moles CaCl2
So, 5 moles of chlorine will react to form 10 moles of calcium chloride.
To calculate the mass of calcium chloride formed, we need to know the molar mass of CaCl2.
The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of chlorine (Cl) is 35.45 g/mol. Since each calcium chloride (CaCl2) formula unit contains 1 calcium atom and 2 chlorine atoms, the molar mass of CaCl2 is:
1(40.08 g/mol) + 2(35.45 g/mol) = 40.08 + 70.9 = 111.38 g/mol
Finally, to calculate the mass of calcium chloride formed, we multiply the number of moles of CaCl2 by its molar mass:
10 moles CaCl2 x (111.38 g/mol) = 1113.8 g
Therefore, the mass of CaCl2 formed when 5 moles of chlorine react with calcium metal is 1113.8 grams.
The balanced equation for the reaction between calcium and chlorine is:
Ca + Cl2 -> CaCl2
The molar ratio between calcium and chlorine is 1:2, which means that for every mole of calcium used, 2 moles of chlorine are required to completely react. Therefore, if 5 moles of chlorine are used, then we need 2.5 moles (5/2 = 2.5) of calcium to completely react with all the chlorine.
The molar mass of CaCl2 is 40.1 + 2(35.5) = 111.1 g/mol.
The mass of CaCl2 formed can be calculated using:
mass = moles x molar mass
mass = 2.5 mol x 111.1 g/mol
mass = 277.75 g
Therefore, 277.75 g of CaCl2 will be formed when 5 moles of chlorine react with calcium metal.