Question

The 14th term of an arithmetic progression is 96 while the 25th term is 173 find the sum of the 13th term and the 56th

Answer 1

a+13d = 96

a+24d = 173
solve for a and d, and then you want
a+12d + a+55d = 2a+67d

Answer 2

T14=96. T25 =173. Nth term TN=at(n-1) d t14=at(14-1)d. T14 =a+(13)d t14=a+13d but t14=96 =a+13d a+13d=96 T25=a+(25-1)d T25 =a+24d T25 =173 173 =a+24d.