Two fair dice are tossed find the probability that the outcome is less than 11, the outcome is at least 10 And one number is odd and the other is prime
What you don't want is 12 or 11
one way to get 12
2 ways to get 11 , so we exclude 3 ways
total number of total ways for 2 dice to fall is 36
prob(of your event) = 1 - 3/36
= 1 - 1/12
= 11/12
use the same kind of analysis for prob(at least 10)
prob(one odd AND the other prime) :
problem: could both be odds? could both be primes ? would 33 satisfy as an example ?