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A cell supplies a current of 0.04 amphere through 2 resistors of resistances 6 and 3 ohms in series.calculate

a)potential difference across each resistor.
b)Terminal voltage of the cell.

V = i R = 0.04 * 6 + 0.04 * 3 = 0.24 volts + 0.12 volts

sum V total = 0.36 volts

Did you know?

Did you know that the potential difference across each resistor in a series circuit can be calculated using Ohm's Law? In this case, the current supplied by the cell is 0.04 amperes, and the resistances of the two resistors are 6 ohms and 3 ohms. To calculate the potential difference, you simply multiply the current by the resistance. Therefore, the potential difference across the 6-ohm resistor would be 0.04 A * 6 Ω = 0.24 volts, and the potential difference across the 3-ohm resistor would be 0.04 A * 3 Ω = 0.12 volts. Additionally, the terminal voltage of the cell in a series circuit is the sum of the potential differences across the resistors. In this case, the terminal voltage would be 0.24 volts + 0.12 volts = 0.36 volts. This is the overall voltage that the cell is supplying to the circuit.