Out of five men and five women, we form a committee consisting of four different people. Assuming that each committee of size four is equally likely, find the probabilities of the following events:
Looks like you are just choosing any 4 of the 9 people, since no conditions
were stated, so that is simply
C(9,4) or 126
9!/(4!5!) = 362880/(24*120) = 126