The minimum fare for a jeepney ride is PHP 11.00 for the first 5 kilometers. A fee of PHP 9.00 will be added for succeeding kilometer. How much will a passenger pay if the distance is (a) 3 kilometers? (b) 26 kilometers? (c) 5 kilometers? (d) 17 kilometers? (e) 30 kilometers?
11 ifx≤5
11+9(x-5) ifx>5
To solve for the fare in each scenario, we can use the given fare structure.
(a) For a distance of 3 kilometers:
Since the distance is less than or equal to 5 kilometers, the fare is PHP 11.00.
(b) For a distance of 26 kilometers:
For the first 5 kilometers, the fare is PHP 11.00.
For the remaining 21 kilometers (26 - 5), PHP 9.00 will be added for each kilometer.
So, the additional fare for the remaining distance is (21 km * PHP 9.00/km) = PHP 189.00.
The total fare would be PHP 11.00 (base fare) + PHP 189.00 (additional fare) = PHP 200.00.
(c) For a distance of 5 kilometers:
Since the distance is equal to 5 kilometers, the fare is PHP 11.00.
(d) For a distance of 17 kilometers:
For the first 5 kilometers, the fare is PHP 11.00.
For the remaining 12 kilometers (17 - 5), PHP 9.00 will be added for each kilometer.
So, the additional fare for the remaining distance is (12 km * PHP 9.00/km) = PHP 108.00.
The total fare would be PHP 11.00 (base fare) + PHP 108.00 (additional fare) = PHP 119.00.
(e) For a distance of 30 kilometers:
For the first 5 kilometers, the fare is PHP 11.00.
For the remaining 25 kilometers (30 - 5), PHP 9.00 will be added for each kilometer.
So, the additional fare for the remaining distance is (25 km * PHP 9.00/km) = PHP 225.00.
The total fare would be PHP 11.00 (base fare) + PHP 225.00 (additional fare) = PHP 236.00.
Therefore, the passenger will pay:
(a) PHP 11.00
(b) PHP 200.00
(c) PHP 11.00
(d) PHP 119.00
(e) PHP 236.00