Which is a zero of the quadratic function f(x)=16x2+32x-9
To find the zeros of a quadratic function, you need to solve the equation f(x) = 0. In this case, the quadratic function is f(x) = 16x^2 + 32x - 9. To find the zeros, follow these steps:
Step 1: Set f(x) equal to zero.
16x^2 + 32x - 9 = 0
Step 2: Factor the quadratic equation.
This can be done by factoring or using the quadratic formula, but in this case, factoring will work:
(4x - 1)(4x + 9) = 0
Step 3: Set each factor equal to zero.
4x - 1 = 0 or 4x + 9 = 0
Step 4: Solve for x in each equation.
For 4x - 1 = 0:
Adding 1 to both sides, we get: 4x = 1
Dividing both sides by 4, we get: x = 1/4
For 4x + 9 = 0:
Subtracting 9 from both sides, we get: 4x = -9
Dividing both sides by 4, we get: x = -9/4
Hence, the zeros of the quadratic function f(x) = 16x^2 + 32x - 9 are x = 1/4 and x = -9/4.