The approximate concentration of hydrochloric acid.HCL in the stomach(stomach acid) is 0.17M.calculate the mass of the following antacids required to naturalize 50cm3 of this acid (a)bicarbonate of soda. NaHCO3 (b)aluminum hydroxide AL(OH)3
I'll do a. You follow the same procedure and do b.
NaHCO3 + HCl ==> NaCl + H2O + CO2
millimoles HCl = mL x M = 50 x 0.17 = 8.5
The reaction is 1:1; therefore, millimoles NaHCO3 needed = 8.5 or 0.0085 moles.
grams NaHCO3 = moles x molar mass = 0.0085 x 84 = 0.714 g
Post your work if you get stuck.