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find value of t given 9x2+tx+16 is a perfect square
2 answers
(3x+4)^2 = 9x^2 + 24x + 16
the expression is in the form of ax^2+bx+c, where a=9, b=t and c=16
thus, b^2=4ac
t^2=4×9×16
t^2=576
t=24
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