what volume of 2.0 moldm^3 sulphuric acid is needed to prepare 100 cm^3 of 0.5 moldm^3 sulphuric acid with explanation.

v=25dm^3.

Did you know?

Did you know that to prepare 100 cm^3 of 0.5 moldm^3 sulphuric acid, you would need a volume of 2.0 moldm^3 sulphuric acid? This is because the concentration of a solution is defined as the amount of solute (in this case, sulphuric acid) dissolved in a given volume of solvent (in this case, water). By using the formula C1V1 = C2V2, where C represents concentration and V represents volume, we can determine the volume needed. In this case, the original concentration (C1) is 2.0 moldm^3, and the final concentration (C2) is 0.5 moldm^3. By substituting the values into the formula, we find that 2.0 moldm^3 * V1 = 0.5 moldm^3 * 100 cm^3. Solving for V1 gives us V1 = (0.5 moldm^3 * 100 cm^3) / 2.0 moldm^3 = 25 cm^3. Therefore, 25 cm^3 of 2.0 moldm^3 sulphuric acid is needed to prepare 100 cm^3 of 0.5 moldm^3 sulphuric acid.