Calculate the ph solution with hydrogen ion concentration of 6.28×10^-6 moldm and 1×10^-5

To calculate the pH of a solution based on the hydrogen ion concentration, you can use the formula:

pH = -log[H+]

where [H+] represents the hydrogen ion concentration.

Case 1:
[H+] = 6.28×10^-6 mol/dm^3

pH = -log(6.28×10^-6)
pH = -(-5.2)
pH ≈ 5.2

Therefore, the pH of the solution with a hydrogen ion concentration of 6.28×10^-6 mol/dm^3 is approximately 5.2.

Case 2:
[H+] = 1×10^-5 mol/dm^3

pH = -log(1×10^-5)
pH = -(-4)
pH ≈ 4

Therefore, the pH of the solution with a hydrogen ion concentration of 1×10^-5 mol/dm^3 is approximately 4.

To calculate the pH of a solution given the hydrogen ion concentration (also known as the acidity or H+ concentration), you can use the equation:

pH = -log[H+]

where [H+] is the hydrogen ion concentration.

Let's calculate the pH for the first hydrogen ion concentration:

pH = -log(6.28×10^-6)

To solve this calculation, you need to take the negative logarithm (base 10) of the hydrogen ion concentration using a scientific calculator or a logarithmic table.

Using a scientific calculator:
pH = -log(6.28×10^-6)
≈ -(-5.2)
≈ 5.2

Hence, the pH of the solution with a hydrogen ion concentration of 6.28×10^-6 moldm is approximately 5.2.

Now, let's calculate the pH for the second hydrogen ion concentration:

pH = -log(1×10^-5)

Again, using a scientific calculator, we can solve this:

pH = -log(1×10^-5)
≈ -(-5)
≈ 5

Therefore, the pH of the solution with a hydrogen ion concentration of 1×10^-5 moldm is approximately 5.

2×2

You didn't finish the question. "and 1E-5 what?"