A fair dice is tossed once, find the probability that it shows 2,an odd number, a prime number, a number less than 4
To find the probability of a specific event occurring, we need to divide the number of favorable outcomes by the total number of possible outcomes.
1. Probability of getting a 2: On a fair six-sided die, there is only one outcome that shows a 2. So, the number of favorable outcomes is 1, and the total number of possible outcomes is 6. Therefore, the probability of getting a 2 is 1/6.
2. Probability of getting an odd number: Out of the six numbers on the die, three are odd (1, 3, and 5). So, the number of favorable outcomes is 3, and the total number of possible outcomes is 6. Therefore, the probability of getting an odd number is 3/6, which simplifies to 1/2.
3. Probability of getting a prime number: There are three prime numbers on a die (2, 3, and 5). Thus, the number of favorable outcomes is 3, and the total number of possible outcomes is 6. Consequently, the probability of rolling a prime number is 3/6, which simplifies to 1/2.
4. Probability of getting a number less than 4: The numbers less than 4 on a die are 1, 2, and 3. So, the number of favorable outcomes is 3, and the total number of possible outcomes is 6. Hence, the probability of obtaining a number less than 4 is 3/6, which also simplifies to 1/2.