A right pyramid on a base 10m Square is 15m high what is its volume? If the top six metre of the pyramid are removed, what is the volume of the remaining frustum
volume of any type of pyramid = (1/3)(base)(height)
Whole pyramid = 1/3 (100^2)(15)
= 50,000 m^3
removed pyramid: need its base,
x/6 = 10/15 -----> x= 60/15 = 4
volume of removed pyramid = (1/3)(4^2)(6) = ...
finish it up