Given that 2and _3 are roots of the equation ax²+bx+c=0, find the values of a, b, c,
If x = 2 , x = -3
then the equation could have been
(x-2)(x+3) = 0
x^2 + x - 6 = 0
So what do you think?
then the equation could have been
(x-2)(x+3) = 0
x^2 + x - 6 = 0
So what do you think?