A farm tractor starting from the rest attains a speed of 36000m/s after covering 2000m . Work out the magnitude of the net force if the tractor weighs 5000kg
F = m*a
and
a = change in velocity / change in time
if a is constant then t = distance / average velocity
To find the magnitude of the net force acting on the tractor, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
Given:
- Mass of the tractor (m) = 5000 kg
- Distance covered (d) = 2000 m
- Final velocity (v) = 36000 m/s
First, you need to calculate the acceleration of the tractor using the following equation:
v^2 = u^2 + 2ad
Where:
- v is the final velocity
- u is the initial velocity (which is zero in this case)
- a is the acceleration
- d is the distance covered
Rearranging the equation, you get:
a = (v^2 - u^2) / (2d)
Plugging in the values, you have:
a = (36000^2 - 0^2) / (2 x 2000)
Now, calculate the acceleration:
a = 648000000 / 4000
a = 162000 m/s^2
With the acceleration value, you can now use Newton's second law to find the net force:
F = m * a
Plugging in the values, you have:
F = 5000 kg * 162000 m/s^2
F = 810000000 N
Therefore, the magnitude of the net force acting on the tractor is 810000000 N.