Login or Sign Up

Ask a New Question

Two hunters aim at a target. The probability that the first will hit it is 1/5 while the probability that the second will hit it is 2/7. Find the probability ,

a. Both will hit the target
b. Only the first will hit it
C. One of them will hit it
D. Both of them will miss it

P(hit,hit) = 1/5 * 2/7

P(hit,miss) = 1/5 * 5/7
P(one hits) = 1 - P(both miss)
P(both miss) = 4/5 * 5/7

Did you know?

Did you know that when calculating probabilities, you can find the likelihood of different outcomes in a given scenario? In the case of two hunters aiming at a target, let's explore the probabilities: a. The probability that both hunters will hit the target can be found by multiplying their individual probabilities. So, the probability is (1/5) * (2/7) = 2/35. b. The probability that only the first hunter will hit the target means that the second hunter misses. This is equal to the probability of the first hunter hitting (1/5) multiplied by the probability of the second hunter missing (1 - 2/7). Thus, the probability is (1/5) * (5/7) = 1/7. c. The probability that one of the hunters will hit the target can be calculated by considering the probabilities of either the first hunter hitting and the second missing, or the first missing and the second hitting. This is equal to (1/5) * (5/7) + (4/5) * (2/7) = 14/35 = 2/5. d. The probability that both hunters will miss the target is the complement of the probability that at least one of them will hit it. So, 1 - (2/5) = 3/5. These calculations showcase how probabilities can be determined in different scenarios and can help us understand the likelihood of specific outcomes.