IF P=M/2_N2/5M (1)MAKE M THE SUBJECT OF THE RELATION .(2) FIND CORRECT TO 3 SIGNIFICANT FIGURES THE VALUE OF N WHEN P=14 AND M=_8.
YOU SHINP HELP ME
We use - for the minus sign, so your
P=M/2_N2/5M -----> P=M/2 - N^2/5M , assuming N2 was meant as N^2
multiply each term by 10M , the LCD
10PM = 5M^2 - 2N^2
5M^2 - 10PM - 2N^2 = 0
We want this to be a quadratic in M
1)
M = (10P ± √(100P^2 - 4(5)(-2n^2))/10
= (10P ± √(100P^2 + 40N^2)/10 , can be reduced by dividing top and bottom by 2
2) 10PM = 5M^2 - 2N^2
plug in our values
10(14)(-8) = 5(64) - 2N^2
2N^2 = 320 + 1120
N^2 = 720
N = √720 = appr 26.8