If p=m\2- n2/5m.make n the subject of the relation. First correct to 3 significant figures,the value of n when p=4 and m=-8

Taking a wild guess at your confusing equation:

p = m/2 - n^2/5
times 10
10p = 5m - 2n^2
2n^2 = 5m - 10p
n^2 = (5m-10p)/2
n = ± √( (5m-10p)/2 )

now plug in the given values of p and m

did you mean:

p = m/2 - n^2/(5m) ?

make the necessary changes in my solution.

Pleas answer it now

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maybe p = (n^2-n^2)/5m

Parentheses make a difference when you don't have text formatting here.

Well, let's see if I can help you with some clownish calculations!

Starting with the given formula: p = (m/2) - (n^2/5m)

To make n the subject of the relation, we need to isolate the variable n. Here's how we can do it:

Step 1: Multiply the equation by 5m to get rid of the denominators:
5mp = 5m(m/2) - n^2

Step 2: Simplify the equation:
5mp = (5m^2)/2 - n^2

Step 3: Move the n^2 term to the left side:
n^2 = (5m^2)/2 - 5mp

Step 4: To isolate n, we take the square root of both sides:
n = √((5m^2)/2 - 5mp)

Now, let's substitute the given values, correcting each step to 3 significant figures as requested:

p = 4 (no need to correct)
m = -8 (no need to correct)

Step 1: 5mp = 5(-8)(-8/2) - n^2
5mp = 20 - n^2

Step 2: n^2 = (5(-8)^2)/2 - 5(-8)p
n^2 = 160/2 + 40p

Step 3: n^2 = 80 + 40p

Step 4: n = √(80 + 40(4))
n = √(80 + 160)
n = √240
n β‰ˆ 15.492

So, approximately correcting the result to 3 significant figures, when p = 4 and m = -8, the value of n is 15.5.

Remember, though, that I'm just a clown bot, so don't take my calculations too seriously!

To solve for n in the equation p = (m/2) - (n^2)/(5m), we will first substitute the given values p = 4 and m = -8 into the equation.

Step 1: Substitute the given values:
4 = (-8/2) - (n^2) / (5 * -8)

Simplifying the equation further, we get:
4 = -4 - (n^2) / (-40)

Step 2: Multiply both sides of the equation by -40 to eliminate the fraction:
-40 * 4 = -40 * (-4) - (-40) * (n^2) / (-40)

-160 = 160 + n^2

Step 3: Rearrange the equation, bringing all terms to one side:
n^2 + 320 = 0

Step 4: Solve for n by factoring or using the quadratic formula. To correct to three significant figures, we will round the value of n.

Using the quadratic formula: n = (-b ± √(b^2 - 4ac)) / (2a), where a = 1, b = 0, and c = 320.

n = (-0 ± √(0 - 4*1*320)) / (2*1)
n = ± √(-1280) / 2

Since the value under the square root is negative, there are no real solutions to the equation. Therefore, there is no real value of n that satisfies the equation when p = 4 and m = -8.