a solution is prepared by dissolving 18g of glucose in 150g of water the resulting solution was found to have boiling point of 100.34c calculate the molarmass of glucose
delta T = i*Kb*molality
delta T = 100.34 - 100 = 0.334
i = 1 for non-volatile solutes
Kb = 0.512
Substitute and solve for m
0.34 = 1*0.512*m
m = approximately 0.664
molality = moles/kg solvent. kg solvent = 0.150. Subsitute and solve for mols.
0.664 = moles/0.150
moles = 0.996. Then mols = g/molar mass. g = 18
0.0996 = 18/molar mass
molar mass = 18/0.0996 = ?