In a class of 50 students . 16 offer Further Mathematics . 41 offer Physics . If 7 neither offer Further Mathematics nor Physics , how many offers both ?
once is enough
see your previous post
To find out how many students offer both Further Mathematics and Physics, we need to subtract the number of students who offer neither subject from the total number of students who offer at least one of the subjects.
Let's break down the given information:
- Total number of students = 50
- Number of students who offer Further Mathematics = 16
- Number of students who offer Physics = 41
- Number of students who offer neither subject = 7
To find the number of students who offer either Further Mathematics or Physics, we can add the number of students who offer Further Mathematics to the number of students who offer Physics: 16 + 41 = 57.
However, since we have counted some students twice (those who offer both subjects), we need to subtract the number of students who offer both subjects.
Therefore, the number of students who offer both Further Mathematics and Physics can be found by subtracting the number of students who offer neither subject from the total number of students who offer at least one subject: 57 - 7 = 50.
So, 50 students offer both Further Mathematics and Physics.