15 ml of 0.25M H2So4 was mixed with 15ml 0.25 M KOH According to the below reaction
2 KOH + H2So4 = K2So4 + 2H2O
How much K2So4 will be produce ?
How many moles of each reactant do you have?
H2SO4: 0.015L * 0.25M = 0.00375 moles
KOH: the same
since the KOH is used up twice as fast, by the time 0.00375 moles of KOH has been used up, only half that much H2SO4 has been consumed. So only 0.001875 moles of K2SO4 will be produced.
Convert that to grams if you wish.