Balance the following acidic medium (a)knno4(aq)+feso4(aq) mnso4(aq)+fe2so4 3(aq)+k2so4(aq)
(B)FECL3(AQ)+SNCL2(AQ) FECL2(AQ)+SNCL4(AQ)
(2)Determine the oxidation number of the centrel atom in the following (a)cuso4(b)hoso4(c)fe(so3)2(d)fe(no3)(e)mnso4(f)no3(g)hno3(h)po34(i)k3fe(cm)6(j)naclo(k)so23(l)slo23(m)clo5(n)n20(o)mnso4(p)nh3(q)co2(r)so2(s)kmno4(t)kclo3
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Here is a tutorial that is very good on balancing equations in acid and basic medium and determining oxidation states of elements in various compounds.
h ttps://www.chemteam.info/ChemTeamIndex.html
After you have gone through the tutorials, please post any questions you have and tell us why you are having trouble.
To balance the given equations, you need to make sure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations for the given reactions:
(a) 2KMnO4(aq) + 5FeSO4(aq) + 8H2SO4(aq) → 5Fe2(SO4)3(aq) + K2SO4(aq) + 2MnSO4(aq) + 8H2O(l)
(b) 2FeCl3(aq) + 3SnCl2(aq) → 2FeCl2(aq) + 3SnCl4(aq)
To determine the oxidation number of the central atom in the given compounds, you need to know the rules for assigning oxidation numbers:
- The oxidation number of an element in its elemental state is always zero (e.g., Fe in Fe).
- The oxidation number of an ion is equal to its charge (e.g., Na+ has an oxidation number of +1).
- The sum of the oxidation numbers in a neutral compound is zero, and in an ion, it is equal to the charge of the ion.
Now, let's determine the oxidation number of the central atom in each compound:
(a) CuSO4: The oxidation number of oxygen is -2, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of copper (Cu) is +2.
(b) H2SO4: The oxidation number of oxygen is -2, and hydrogen is usually +1. To balance the equation, sulfur (S) must have an oxidation number of +6.
(c) Fe(SO3)2: The oxidation number of oxygen is -2, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of iron (Fe) is +2.
(d) Fe(NO3)2: The oxidation number of oxygen is -2, and nitrate (NO3-) is a polyatomic ion with a charge of -1. To balance the equation, the oxidation number of iron (Fe) must be +2.
(e) MnSO4: The oxidation number of oxygen is -2, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of manganese (Mn) is +2.
(f) NO3-: The oxidation number of oxygen is -2, and NO3- has a charge of -1. To balance the equation, the oxidation number of nitrogen (N) must be +5.
(g) HNO3: The oxidation number of oxygen is -2, and hydrogen is usually +1. To balance the equation, nitrogen (N) must have an oxidation number of +5.
(h) PO3-4: The oxidation number of oxygen is -2, and PO3-4 has a charge of -3. To balance the equation, the oxidation number of phosphorus (P) must be +5.
(i) K3[Fe(CN)6]: The oxidation number of potassium (K) and cyanide (CN-) are known. To balance the equation, the oxidation number of iron (Fe) must be +2.
(j) NaClO: The oxidation number of oxygen is -2, and NaClO has a charge of 0 (neutral compound). To balance the equation, the oxidation number of chlorine (Cl) must be +1.
(k) SO2-3: The oxidation number of oxygen is -2, and SO2-3 has a charge of -2. To balance the equation, the oxidation number of sulfur (S) must be +4.
(l) Slo2-3: The oxidation number of oxygen is -2, and Slo2-3 has a charge of -2. To balance the equation, the oxidation number of sulfur (S) must be +4.
(m) ClO5-: The oxidation number of oxygen is -2, and ClO5- has a charge of -1. To balance the equation, the oxidation number of chlorine (Cl) must be +5.
(n) N2O: The oxidation number of oxygen is -2, and N2O has a charge of 0 (neutral compound). To balance the equation, the oxidation number of nitrogen (N) must be +1.
(o) MnSO4: The oxidation number of oxygen is -2, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of manganese (Mn) is +2.
(p) NH3: The oxidation number of hydrogen is +1, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of nitrogen (N) is -3.
(q) CO2: The oxidation number of oxygen is -2, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of carbon (C) is +4.
(r) SO2: The oxidation number of oxygen is -2, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of sulfur (S) is +4.
(s) KMnO4: The oxidation number of oxygen is -2, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of potassium (K) is +1, and the oxidation number of manganese (Mn) is +7.
(t) KClO3: The oxidation number of oxygen is -2, and since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of potassium (K) is +1, and the oxidation number of chlorine (Cl) is +5.
Remember, the oxidation numbers are not always straightforward, and they may vary depending on the compounds and their charges.