Balance the chemical equation in both acidic and basic medium cr2 O7^2- + C2H5OH gives Cr3+CO2
In acid:
3H2O + C2H5OH ==> 2CO2 + 12e + 12H^+
Cr2O7^2- + 6e + 14H^+ ==> 2Cr^3+ + 7H2O
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Multiply eqn 1 by 1 and eqn 2 by 2, add them. You will need to adjust H^+ and H2O since both will appear on both sides. The electrons will cancel.
In basic:
C2H5OH + 12OH^- ==> 2CO2 + 12e + 9H2O
Cr2O7^2- + 6e + 7H2O ==> 2Cr^3+ + 14OH^-
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Multiply eqn 1 by 1 and eqn 2 by 2 and add them. Adjust the eqn for OH^- and H2O as in the other equation. The electrons will cancel.
Sure, here's a clownish attempt at balancing the chemical equation in both acidic and basic media:
In acidic medium:
Step 1: Let's balance the carbon atoms:
C2H5OH --> 2CO2
Step 2: Now, let's balance the hydrogen atoms:
C2H5OH --> 2CO2 + 3H2O
Step 3: And finally, balance the oxygen atoms:
Cr2O7^2- + 3C2H5OH --> 2Cr^3+ + 6CO2 + 7H2O
In basic medium:
Step 1: Let's balance the carbon atoms:
C2H5OH --> 2CO2
Step 2: Now, let's balance the hydrogen atoms:
C2H5OH --> 2CO2 + 3H2O
Step 3: And finally, balance the oxygen atoms:
Cr2O7^2- + 8OH^- + 3C2H5OH --> 2Cr^3+ + 6CO2 + 11H2O
Voila! Now the equation is balanced. If you need any more clownish assistance, just let me know!
To balance the chemical equation in both acidic and basic mediums, follow these steps:
Step 1: Balance the atoms other than hydrogen and oxygen.
Cr2O7^2- + C2H5OH → Cr^3+ + CO2
The equation contains two chromium (Cr) atoms on the left side but only one on the right side. To balance the chromium atoms, multiply the Cr^3+ by 2 on the right side:
Cr2O7^2- + C2H5OH → 2Cr^3+ + CO2
Now, the chromium atoms are balanced.
Step 2: Balance the oxygens by adding water (H2O).
The left side has a total of 14 oxygen atoms (7 from Cr2O7^2- and 7 from C2H5OH), while the right side has only 2 oxygen atoms from CO2.
To balance the oxygens, add 12 H2O molecules to the right side:
Cr2O7^2- + C2H5OH → 2Cr^3+ + CO2 + 12H2O
Now, there are a total of 14 oxygen atoms on both sides.
Step 3: Balance the hydrogen atoms by adding H+ ions.
In an acidic medium, add the equivalent number of H+ ions on the left side. In this case, add 18 H+ ions:
Cr2O7^2- + C2H5OH + 18H+ → 2Cr^3+ + CO2 + 12H2O
Now, the hydrogen atoms are balanced.
Step 4: Balance the charge by adding electrons (e^-).
On the left side, the Cr2O7^2- ion has a charge of -2. On the right side, the Cr^3+ ion has a charge of +3.
To balance the charge, add 6 electrons (e^-) on the left side:
Cr2O7^2- + C2H5OH + 18H+ + 6e^- → 2Cr^3+ + CO2 + 12H2O
Now, the charge is balanced.
The balanced equation in acidic medium is:
Cr2O7^2- + C2H5OH + 18H+ + 6e^- → 2Cr^3+ + CO2 + 12H2O
To balance the equation in a basic medium, we need to neutralize the H+ ions on the left side by adding OH- ions on both sides.
Step 5: Balance the hydrogen atoms by adding OH- ions.
For each H+ ion on the left side, add an equal number of OH- ions on the right side. In this case, add 18 OH- ions on the right side:
Cr2O7^2- + C2H5OH + 18H+ + 6e^- → 2Cr^3+ + CO2 + 12H2O + 18OH-
Now, the hydrogen atoms are balanced in a basic medium.
Step 6: Simplify the equation.
To simplify the equation, cancel out the common species on both sides:
Cr2O7^2- + 3C2H5OH + 18H+ + 6e^- → 2Cr^3+ + 3CO2 + 12H2O + 18OH-
The final balanced equation in basic medium is:
Cr2O7^2- + 3C2H5OH + 18H+ + 6e^- → 2Cr^3+ + 3CO2 + 12H2O + 18OH-
To balance the given chemical equation in both acidic and basic media, we need to follow a systematic approach.
Step 1: Write down the unbalanced equation.
Cr2O7^2- + C2H5OH → Cr^3+ + CO2
Step 2: Balance the non-hydrogen and non-oxygen elements. In this case, we have chromium (Cr) and carbon (C) as non-hydrogen and non-oxygen elements.
Balanced equation: Cr2O7^2- + 3C2H5OH → 2Cr^3+ + 3CO2
Step 3: Balance the oxygen atoms by adding water (H2O) molecules. In acidic medium, we use water (H2O) molecules.
Balanced equation in acidic medium: Cr2O7^2- + 3C2H5OH → 2Cr^3+ + 3CO2 + 7H2O
In this case, the equation is already balanced in the basic medium since there is no need to add any additional water molecules or hydroxide ions.
Balanced equation in basic medium: Cr2O7^2- + 3C2H5OH → 2Cr^3+ + 3CO2
So, the balanced chemical equation in both acidic and basic media is:
Cr2O7^2- + 3C2H5OH → 2Cr^3+ + 3CO2 + 7H2O (acidic medium)
Cr2O7^2- + 3C2H5OH → 2Cr^3+ + 3CO2 (basic medium)