An object is moving horizontally to the right with a constant velocity of 1.50 m / s. A force of 5.00 N on the object is in the same direction with its velocity. There is no friction. a) Identify all the forces in the horizontal direction in magnitude and direction. b) What distance will the object cover is 12.5 s?
You need the mass m
ui = initial x speed = 1.50 m/s
Fx = m Ax = 5 Newtons, also equal and opposite force back on the pusher guy
so
Ax = 5 / m meters/second^2
u = ui + Ax t = 1.50 + (5/m) * t
x = ui t + (2.5 / m) t^2 = 1.5 (12.5) + (2.5 / m) (12.5)^2