3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl
1. How many grams of Na³PO⁴ are needed to react with 4 moles of CaCl² ?
2. How many grams of CaCl² are needed to react with 6 moles of Na³PO⁴ ?
3. How many grams of Ca³ (PO⁴)² will produce by 8 moles of Na³PO⁴?
3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl
1. How many grams of Na³PO⁴ are needed to react with 4 moles of CaCl² ?
Convert moles CaCl2 you have to moles Na3PO4 needed by using the coefficients in the balanced equation this way.
4 mols CaCl2 x (2 moles Na3PO4/3 moles CaCl2) = 4 x 2/3 = ?
Then grams Na3PO4 = moles Na3PO4 x molar mass Na3PO4.
2 and 3 are worked the same way. Post your work if you get stuck.
I still don't understand
To find the mass of a substance required or produced in a chemical reaction, we need to use stoichiometry. Stoichiometry is a method that allows us to calculate the quantities of reactants and products involved in a chemical reaction.
Given the balanced equation: 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl, we can use the stoichiometric coefficients to determine the relationship between different substances involved.
1. To find the grams of Na3PO4 needed to react with 4 moles of CaCl2:
- Identify the stoichiometric ratio between Na3PO4 and CaCl2 from the balanced equation: 2 moles of Na3PO4 react with 3 moles of CaCl2.
- Set up a proportion to find the moles of Na3PO4 needed:
(4 moles of CaCl2 / 3 moles of Na3PO4) = (x moles of CaCl2 / 2 moles of Na3PO4)
- Solve for x to find the moles of Na3PO4 needed:
x = (4 moles of CaCl2 / 3) * (2 moles of Na3PO4 / 1 mole of CaCl2) = 8/3 moles of Na3PO4
- To convert moles to grams, multiply the moles of Na3PO4 by its molar mass (sodium phosphate: Na3PO4).
2. To find the grams of CaCl2 needed to react with 6 moles of Na3PO4:
- Identify the stoichiometric ratio between CaCl2 and Na3PO4 from the balanced equation: 3 moles of CaCl2 react with 2 moles of Na3PO4.
- Set up a proportion to find the moles of CaCl2 needed:
(6 moles of Na3PO4 / 2 moles of CaCl2) = (x moles of Na3PO4 / 3 moles of CaCl2)
- Solve for x to find the moles of CaCl2 needed:
x = (6 moles of Na3PO4 / 2) * (3 moles of CaCl2 / 1 mole of Na3PO4) = 9 moles of CaCl2
- To convert moles to grams, multiply the moles of CaCl2 by its molar mass (calcium chloride: CaCl2).
3. To find the grams of Ca3(PO4)2 produced by 8 moles of Na3PO4:
- Identify the stoichiometric ratio between Na3PO4 and Ca3(PO4)2 from the balanced equation: 2 moles of Na3PO4 produce 1 mole of Ca3(PO4)2.
- Set up a proportion to find the moles of Ca3(PO4)2 produced:
(8 moles of Na3PO4 / 2 moles of Ca3(PO4)2) = (x moles of Na3PO4 / 1 mole of Ca3(PO4)2)
- Solve for x to find the moles of Ca3(PO4)2 produced:
x = (8 moles of Na3PO4 / 2) * (1 mole of Ca3(PO4)2 / 1 mole of Na3PO4) = 4 moles of Ca3(PO4)2
- To convert moles to grams, multiply the moles of Ca3(PO4)2 by its molar mass (calcium phosphate: Ca3(PO4)2).
Remember to use the periodic table to find the molar masses of the elements and compounds involved in the calculations.