Using the following balanced equation, how many moles of NaCl can be produced from 0.314 moles of Na3PO4?
3 FeCl2 + 2 Na3PO4 → 6 NaCl + Fe3(PO4)2
_____ mole NaCl produced
0.314 moles of Na3PO4 can produce 5 moles of NaCl.
Well, according to the balanced equation, 2 moles of Na3PO4 can produce 6 moles of NaCl. So, if you have 0.314 moles of Na3PO4, you can calculate the number of moles of NaCl by using a simple ratio.
(0.314 moles Na3PO4) x (6 moles NaCl / 2 moles Na3PO4) = 0.942 moles NaCl
Therefore, 0.942 moles of NaCl can be produced from 0.314 moles of Na3PO4.
To determine the number of moles of NaCl produced, we need to use the balanced equation and the given amount of Na3PO4.
First, let's examine the balanced equation:
3 FeCl2 + 2 Na3PO4 → 6 NaCl + Fe3(PO4)2
According to this equation, 2 moles of Na3PO4 produce 6 moles of NaCl.
Now, we can set up a proportion using the given information:
2 moles Na3PO4 = 6 moles NaCl
0.314 moles Na3PO4 = x moles NaCl
To solve for x, we can use the following equation:
0.314 moles Na3PO4 * (6 moles NaCl / 2 moles Na3PO4) = x moles NaCl
Calculating this expression:
0.314 * (6/2) = x
0.314 * 3 = x
0.942 = x
Therefore, 0.942 moles of NaCl can be produced from 0.314 moles of Na3PO4.
5
3 FeCl2 + 2 Na3PO4 → 6 NaCl + Fe3(PO4)2
The coefficients in the balanced equation tell you. Do this.
0.314 mols Na3PO4 x (6 mols NaCl/2 mols Na3PO4) = ? mols NaCl.