How many mole of H2O are required to produce 4.5 moles of HNO3 according to the ff reaction?
3NO3 + H2O = 2HNO3 + NO
well, it takes 1/2 as many moles of H2O as it produces HNO3
so, what's 1/2 of 4.5?
I'm familiar with N2O, NO, NO2, N2O3, N2O4, and N2O5 but NO3 is a new one on me. Let me point out that the equation is not balanced so oobleck gave you the right answer for the equation you posted but your equation is wrong to start.
I am betting on NO2 :)
To determine the number of moles of H2O required to produce 4.5 moles of HNO3, we need to use the stoichiometry of the given balanced chemical equation.
Looking at the equation:
3NO3 + H2O = 2HNO3 + NO
We can see that for every 3 moles of HNO3 produced, 1 mole of H2O is consumed. Therefore, the mole ratio between H2O and HNO3 is 1:3.
To calculate the moles of H2O required, we can set up a proportion using the given information:
(4.5 moles HNO3 / 2 moles HNO3) = (x moles H2O / 1 mole H2O)
Solving for x:
(4.5 moles HNO3 / 2 moles HNO3) * (1 mole H2O / 1 mole H2O) = x moles H2O
(4.5/2) * 1 = x
x = 2.25 moles H2O
Therefore, 2.25 moles of H2O are required to produce 4.5 moles of HNO3 according to the given reaction.