an object that has lost 3 electrons is 0.003m north of an object that has gained 2 electrons. what is the value and direction of the force acting on the object that had gained 2 electrons?
To determine the value and direction of the force acting on the object that gained 2 electrons, we can use Coulomb's law. Coulomb's law states that the force between two charged objects is given by the formula:
F = (k * |q1 * q2|) / r^2
Where:
F is the force between the objects,
k is the electrostatic constant (k ≈ 9 x 10^9 Nm^2/C^2),
q1 and q2 are the charges of the objects (in Coulombs),
|r| is the distance between the objects (in meters).
In this case, the object that lost 3 electrons has a net positive charge, and the object that gained 2 electrons has a net negative charge. Electrons have a charge of -1.6 x 10^-19 Coulombs. So, the charge of the object that lost 3 electrons would be (3 * 1.6 x 10^-19 C), and the charge of the object that gained 2 electrons would be (-2 * 1.6 x 10^-19 C).
Given that the distance between the objects is 0.003 meters (north), we can plug these values into the formula and calculate the force:
F = (k * |q1 * q2|) / r^2
F = (9 x 10^9 Nm^2/C^2) * |(3 * 1.6 x 10^-19 C) * (-2 * 1.6 x 10^-19 C)| / (0.003 m)^2
Simplifying the equation yields:
F = (9 x 10^9 Nm^2/C^2) * (3 * 1.6 x 10^-19 C) * (2 * 1.6 x 10^-19 C) / (0.003^2 m^2)
Evaluating the expression will give you the value of the force in Newtons. The direction of the force will be towards the object that gained 2 electrons, which is north in this case.