calculate the KSP for
Zinc phosphate if
1.18×10^-4 grams of
Zinc phosphate dissolve
to make 2.0 liters of a
saturated solution.
molar mass Zn3(PO4)2 = 386.11 but check that.
M moles/L = 1.18E-4 g/386.11 = 3.06E-7
..............Zn3(PO4)2 ---> 3Zn^2+ + 2PO4^3-
I.................solid.................0................0
C................solid-x..............3x...............2x
E.................solid.................3x..............2x
Ksp = (Zn^2+)^3(PO4^3-)^2
Ksp = (3x)^3(2x)^2 = 108x^5. You know from above that x = 3.06E-7 M Substitute and solve for Ksp.