Adam spends $24.70 on a sticker, a marble and a bead. The marble costs $1.20 more than the bead. The sticker costs 1/3 as much as the marble. What is the cost of 3 stickers, 2 marbles and 4 beads?
s+m+b = 24.70
m = b + 1.20
s = 1/3 m
Now solve for s,m,b and you want 3s+2m+4b
Post your work if you get stuck
let x = cost of a bead
x + 1.2 = cost of a marble
1/3 (x + 1.2) = cost of a sticker
[x + x + 1.2 + x/3 + 1.2/3 = 24.7]3
3x + 3x + 3.6 + x + 1.2 = 74.1
7x = 74.1 - 3.6 - 1.2
7x = 69.3
x = 69.3/7
x = 9.9
x + 1.2 = 11.1
(x + 1.2)/3 = 3.7
Cost of 3 stickers, 2 marbles and 4 beads
= 3(3.7) + 2(11.1) + 4(9.9)
= 11.1 + 22.2 + 39.6
= $72.9
To find the cost of 3 stickers, 2 marbles, and 4 beads, we need to first determine the individual costs of each item.
Let's start by finding the cost of the marble. We know that it costs $1.20 more than the bead. Let's say the cost of the bead is x. Therefore, the cost of the marble will be x + $1.20.
Now let's find the cost of the sticker. We are given that the sticker costs 1/3 as much as the marble. So, the cost of the sticker will be (1/3) * (x + $1.20).
The total cost of the 3 stickers is 3 times the cost of one sticker, which is 3 * [(1/3) * (x + $1.20)] = (x + $1.20).
The total cost of the 2 marbles is 2 times the cost of one marble, which is 2 * (x + $1.20) = 2x + $2.40.
The total cost of the 4 beads is 4 times the cost of one bead, which is 4 * x.
Finally, to find the total cost of 3 stickers, 2 marbles, and 4 beads, we sum up the costs:
Total cost = (x + $1.20) + (2x + $2.40) + (4x).
Now we can substitute the given values to find the answer.
We are given that Adam spends $24.70 on the sticker, marble, and bead. So, we have the equation:
(x + $1.20) + (2x + $2.40) + (4x) = $24.70.
Solving this equation will give us the value of x, which is the cost of the bead. Then, we can substitute this value back into the expressions for the cost of the marble and sticker to find their respective costs. Finally, we can calculate the total cost of 3 stickers, 2 marbles, and 4 beads by substituting these values into the expression mentioned earlier.