We can calculate the amount of freezing point depression that will occur using the following equation:
ΔT = ikfm
where ΔT is the amount of the change in the freezing point, i is the number of particles dissolved, kf is a constant (different for each solvent), and m is the concentration of dissolved material. This concentration has units of mol per kg solvent.
With this in mind, lets calculate the amount of depression that will occur when 5 g of sodium chloride is dissolved into 0.250 kg of water. Remember when sodium chloride dissolves in water it breaks into two particles. The kf for water is 1.86 0C/m.
Report you answer with two decimal points and no units.
ΔT = i*Kf*m
ΔT = ?
i for NaCl is 2.
Kf = 1.86
m = moles/kg = (5 g/58.5)/0.250
Plug and chug.
Question, How did you get 2. for I? Was the number based on the melting or boiling points of the salt or something else completely?
To calculate the amount of freezing point depression, we can use the formula ΔT = ikfm.
In this case, we are given that 5 g of sodium chloride is dissolved into 0.250 kg of water, and sodium chloride breaks into two particles when dissolved in water. The kf value for water is 1.86 °C/m.
First, we need to convert the mass of sodium chloride to moles. The molar mass of sodium chloride is 58.44 g/mol. Therefore, 5 g of sodium chloride is equal to 5/58.44 = 0.0856 mol.
Next, we can substitute the values into the formula:
ΔT = (2) x (1.86 °C/m) x (0.0856 mol/0.250 kg)
ΔT = 0.4888 °C
So, the amount of freezing point depression that will occur when 5 g of sodium chloride is dissolved into 0.250 kg of water is approximately 0.49 °C.