Determine the mass of carbon (v) oxide co2 provided of burning 10kg of ethyne c2h2 (C=12,O=16,H=1)

There is no carbon(v) oxide. CO2 is carbon (iv) oxide.

2C2H2 + 5O2 ==> 4CO2 + 2H2O
moles ethyne = grams/molar mass = 10,000/26 = about 385 but you should do that more accurately.
Convert to mols CO2. That's 385 mols C2H2 x (4 mols CO2/2 moles C2H2) = 385 x 2 = 769.
Convert to grams CO2. That's mols CO2 x molar mass CO2 = ?