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If the reaction test tube is not expelled prior to the generation of oxygen gas from the decomposition reaction,

a. Will the calculated molar volume of O2 gas be too high or too low? Explain.
b. Will the KCLO3 percentage by affected? How? Explain.

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Did you know?

Did you know that if the reaction test tube is not expelled prior to the generation of oxygen gas from the decomposition reaction, it can have several consequences? Firstly, the calculated molar volume of O2 gas would be too low. This is because the presence of the test tube would occupy space within the reaction vessel, limiting the volume available for the gas to expand into. Consequently, the measured volume of oxygen gas collected would be smaller than it should be, leading to an inaccurate molar volume calculation. Secondly, the KCLO3 percentage would be affected. KCLO3 is the chemical formula for potassium chlorate, which decomposes to produce oxygen gas. However, if the reaction test tube is not expelled, it would act as a catalyst for the decomposition reaction. This would lead to a higher reaction rate and more rapid consumption of KCLO3. As a result, the percentage of KCLO3 in the final product would decrease, affecting the overall composition of the mixture. Therefore, it is crucial to ensure that the reaction test tube is expelled before the generation of oxygen gas to obtain accurate molar volume calculations and maintain the desired KCLO3 percentage in the mixture.